ASP.NET Guestbook - Feeding the Database

(Page 5 of 8 )


When the user clicks the Link Label (llPost), data posting starts. We handle it by implementing the LLPOST.CLICK event handler as given below:


Private Sub llPost_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles llPost.Click
       Line1: Dim insertData As DataRow = DataSet11.Tables("feedback").NewRow 'create a new row
        'populate the datarow with data from the form
Line2:        insertData("name") = txtName.Text
Line3:        insertData("email") = txtEmail.Text
Line4:        insertData("comments") = txtComments.Text
Line5:        insertData("rating") = CInt(ddnRating.SelectedItem.Value)
Line6:        DataSet11.Tables("feedback").Rows.Add(insertData) 'add the  populated row to the dataset
        Try
Line7:           SqlDataAdapter1.Update(DataSet11.Tables("feedback")) 'update the database
            'always close the connection
Line8:            SqlConnection1.Close()
Line9:            Response.Redirect("viewcomments.aspx", True)
Line10:        Catch ex As SqlClient.SqlException
            'do something here
Line11:        Catch ex As Exception
            'do something here
Line12:        End Try
    End Sub



Line 1: creates a new data row to insert the post data

Line 2 - Line 5: Populates the data row with the inputs gathered from the users

Line 6: Adds the data row to the dataset(Dataset11)

Line 7: User inputs will not be fed to the database unless you call the adapter’s update method. We do it in this line

Line 8: Always close the connection. Note the fact that we have included Codes inside a try and catch block.

Line 9: Redirect the users another page

Line 10 – Line 11: Catch the exception

Next: Viewing Guestbook: viewcomments.aspx >>
 

More ASP.NET Code Articles
More By R. Abhiram Vikrant

Comments On: ASP.NET Guestbook

>>> Be the FIRST to comment on this article!