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ASP.NET

Dealing with Attributes and Elements in XPath with XSLT using ASP.NET 2.0
By: Jagadish Chaterjee
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    2007-01-09

    Table of Contents:
  • Dealing with Attributes and Elements in XPath with XSLT using ASP.NET 2.0
  • Retrieving all values of a particular attribute at any level of hierarchy (or path)
  • Retrieving all values of all attributes available at any level of hierarchy (or path)
  • Retrieving values of attributes and elements simultaneously
  • Displaying an HTML table based on the hierarchy
  • Searching for an element at a particular location

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    Dealing with Attributes and Elements in XPath with XSLT using ASP.NET 2.0 - Searching for an element at a particular location


    (Page 6 of 6 )

    In this final section, I would like to deal with the elements available at a particular location. That means I would like provide a transformation for an “nth” element.

    To work with the position (or index) of elements, we need to work with an XPath function called “position().”  The following is the first approach we can use to accomplish the task (using separate templates).

    <?xml version="1.0" encoding="utf-8"?>

    <xsl:stylesheet version="1.0"

        xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

          <xsl:template match="/">

                      <xsl:apply-templates select ="EmployeeDetails/Department[position() = 2]"/>

          </xsl:template>

          <xsl:template match="EmployeeDetails/Department">

                <b>Department: <xsl:value-of select ="@Dname"/></b><hr />

                <xsl:apply-templates select ="Employee"/>

                <br/>

          </xsl:template>

          <xsl:template match ="Employee"     >

                <xsl:value-of select ="Empno"/>,

                <xsl:value-of select ="Ename"/>,

                <xsl:value-of select ="Sal"/><br />

          </xsl:template>

         

    </xsl:stylesheet>

    From the above, you can understand that I specified that the position must be 2 (or the second element).  The following is the second approach we can use to deal with the same task (using an “xsl:for-each” construct):

    <?xml version="1.0" encoding="utf-8"?>

    <xsl:stylesheet version="1.0"

        xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

          <xsl:template match="/">

                      <xsl:for-each select="EmployeeDetails/Department[position() = 2]">

                            <b>

                                  Department: <xsl:value-of select ="@Dname"/>

                            </b>

                            <hr />

                            <xsl:for-each select="Employee">

                                  <xsl:value-of select ="Empno"/>,

                                  <xsl:value-of select ="Ename"/>,

                                  <xsl:value-of select ="Sal"/><br />

                            </xsl:for-each>

                            <br />

                      </xsl:for-each>

          </xsl:template>

    </xsl:stylesheet>

    In any of the above cases, when the XSLT gets executed, the transformation would look something like the following:

    <b>   Department: Sales</b>

    <hr />

    2001, Dhanam, 4500<br />

    2002, Chinna, 3400<br />

    2003, Pedda, 3200<br />

    <br />

    I hope you enjoyed the article and any comments, suggestions, feedback, bugs, errors, enhancements etc. are highly appreciated at http://jagchat.spaces.live.com


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