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ASP.NET

Learning XPath with XSLT using ASP.NET 2.0
By: Jagadish Chaterjee
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    2007-01-02

    Table of Contents:
  • Learning XPath with XSLT using ASP.NET 2.0
  • Setting up your environment: XML Schema and XML
  • Setting up your environment: ASP.NET 2.0 code and XSL
  • Retrieving all values of a particular element at a particular level of hierarchy (or path)
  • Retrieving all values of a particular element at any level of hierarchy (or path)
  • Retrieving all values of all elements at all levels of hierarchies (or paths)

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    Learning XPath with XSLT using ASP.NET 2.0 - Setting up your environment: ASP.NET 2.0 code and XSL


    (Page 3 of 6 )

    In the previous section, we completed setting up the XML schema and XML document. Now it is time to modify our ASP.NET 2.0 code to work with a simple XSL focusing on the XML document provided in the previous section.

    Add a new button to your ASP.NET 2.0 project and add the following code to the button click event:

    Protected Sub Button2_Click(ByVal sender As Object, ByVal e As System.EventArgs) Handles Button2.Click

        Dim XSLTFileName As String = Server.MapPath("EmpDetails01.xsl")

        Dim XMLFileName As String = Server.MapPath("EmployeeDetails.xml")

        Dim docXML As New XmlDocument

        docXML.Load(XMLFileName)

        Me.txtXML.Text = docXML.InnerXml

        Dim xp As New XPath.XPathDocument(New XmlTextReader(New IO.StringReader(docXML.InnerXml)))

        Xml1.XPathNavigator = xp.CreateNavigator

        Xml1.TransformSource = XSLTFileName

        '----------------------------------------> generating XSLT to show to user

        Dim xslt As New Xsl.XslCompiledTransform()

        xslt.Load(XSLTFileName)

        ' Create the writer.

        Dim settings As New XmlWriterSettings()

        settings.Indent = True

        settings.IndentChars = ControlChars.Tab

        settings.ConformanceLevel = ConformanceLevel.Auto

        Dim sw As New IO.StringWriter

        Dim writer As XmlWriter = XmlWriter.Create(sw, settings)

        ' Execute the transformation.

        xslt.Transform(docXML, writer)

        writer.Close()

        Me.Literal1.Text = "<pre>" & Server.HtmlEncode(sw.ToString) & "</pre>"

        sw.Close()

      End Sub

    The above code not only transforms your XML to XSL, but also displays the transformation to the user. The following is a sample XSL to test with the above ASP.NET 2.0 code:

    <?xml version="1.0" encoding="utf-8"?>

    <xsl:stylesheet version="1.0"

        xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

          <xsl:template match="/">

                <b>

                      <xsl:value-of select="EmployeeDetails/Department/Employee/Ename"/>

                </b>

          </xsl:template>

    </xsl:stylesheet>

    Once the above code is executed, your transformation should look something like the following:

    <b>Jagadish</b>

    If you are able to view the transformation as above, your setup is correct.

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