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ASP.NET

Learning XPath with XSLT using ASP.NET 2.0
By: Jagadish Chaterjee
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    2007-01-02

    Table of Contents:
  • Learning XPath with XSLT using ASP.NET 2.0
  • Setting up your environment: XML Schema and XML
  • Setting up your environment: ASP.NET 2.0 code and XSL
  • Retrieving all values of a particular element at a particular level of hierarchy (or path)
  • Retrieving all values of a particular element at any level of hierarchy (or path)
  • Retrieving all values of all elements at all levels of hierarchies (or paths)

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    Learning XPath with XSLT using ASP.NET 2.0 - Retrieving all values of a particular element at a particular level of hierarchy (or path)


    (Page 4 of 6 )

    Let us go through our XSL sample listed in the previous section:

    <?xml version="1.0" encoding="utf-8"?>

    <xsl:stylesheet version="1.0"

        xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

          <xsl:template match="/">

                <b>

                      <xsl:value-of select="EmployeeDetails/Department/Employee/Ename"/>

                </b>

          </xsl:template>

    </xsl:stylesheet>

    According to the above, I defined a template to display some information when the control starts at “root” (or “/”). Within the template, I am displaying the value of “EmployeeDetails/Department/Employee/Ename.” In this case, it starts right from the root, proceeds along the path and finds the first employee name. The same gets displayed to the user.

    Now, let us consider that I would like to display all the employee names. We have two good solutions for achieving the same. The first solution will use a separate template for that “Ename” element. You can observe the following code:

    <?xml version="1.0" encoding="utf-8"?>

    <xsl:stylesheet version="1.0"

        xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

          <xsl:template match="/">

                <b>

                      <xsl:apply-templates select ="EmployeeDetails/Department/Employee/Ename"/>

                </b>

          </xsl:template>

          <xsl:template match="EmployeeDetails/Department/Employee/Ename">

                <xsl:value-of select ="text()"/><br/>

          </xsl:template>

    </xsl:stylesheet>

    The other method involves using “xsl:for-each.” If you are new to this construct, I suggest you go through the third and fourth articles of my previous series. The following is the code to achieve the same:

    <?xml version="1.0" encoding="utf-8"?>

    <xsl:stylesheet version="1.0"

        xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

          <xsl:template match="/">

                <b>

                      <xsl:for-each select="EmployeeDetails/Department/Employee/Ename">

                            <xsl:value-of select="text()"/>

                            <br/>

                      </xsl:for-each>

                </b>

          </xsl:template>

    </xsl:stylesheet>

    In either of the above cases, when the XSLT gets executed, the transformation looks something like the following:

    <b>

          Jagadish<br />

          Chatarji<br />

          Winner<br />

          Dhanam<br />

          Chinna<br />

          Pedda<br />

          Ram<br />

          Robert<br />

          Rahim<br />

    </b>

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